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The average of d, e, f and g is 40. If the average of d and e is 14, then what will be the average of f and g?
Question

The average of d, e, f and g is 40. If the average of d and e is 14, then what will be the average of f and g?

A.

66

B.

67

C.

69

D.

72

Correct option is A

Solution:

Average of d, e, f, and g =  d+e+f+g4 \frac{d + e + f + g}{4} \\

40=d+e+f+g4d+e+f+g=16040 = \frac{d + e + f + g}{4} \\d + e + f + g = 160 \\​​
Average of d and e = d+e2\frac{d + e}{2} \\ 

14=d+e2d+e=28f+g=160(d+e)f+g=16028f+g=13214 = \frac{d + e}{2} \\d + e = 28 \\f + g = 160 - (d + e) \\f + g = 160 - 28 \\f + g = 132 \\​​
Average of f and gf+g2=1322=66\frac{f + g}{2} = \frac{132}{2} = 66

​​​

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