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    The areas of three adjacent faces of a solid cuboid are 260cm2, 104cm2 and 10cm2.260 cm^2, \ 104 cm^2\ and \ 10 cm^2. 260cm2, 104
    Question

    The areas of three adjacent faces of a solid cuboid are 260cm2, 104cm2 and 10cm2.260 cm^2, \ 104 cm^2\ and \ 10 cm^2. ​What is the volume (in cm3) of the cuboid?

    A.

    627

    B.

    520

    C.

    524

    D.

    782

    Correct option is B

    Given:

    The areas of the three adjacent faces of a cuboid are:

    a × b = 260 cm², b × c = 104 cm², c × a = 10 cm²

    Formula Used:

    V = a × b × c

    Solution:

    By multiplying the areas of the three faces:

    (a × b) × (b × c) × (c × a) = 260 × 104 × 10

    (a² × b² × c²) = 260 × 104 × 10

    (a × b × c)² = 260 × 104 × 10

    a × b × c = sqrt(260 × 104 × 10)

    Volume = 520 cm³

    Therefore, the volume of the cuboid is:

    Volume = 520 cm³

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