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The areas of three adjacent faces of a solid cuboid are 260cm2, 104cm2 and 10cm2.260 cm^2, \ 104 cm^2\ and \ 10 cm^2. 260cm2, 104
Question

The areas of three adjacent faces of a solid cuboid are 260cm2, 104cm2 and 10cm2.260 cm^2, \ 104 cm^2\ and \ 10 cm^2. ​What is the volume (in cm3) of the cuboid?

A.

627

B.

520

C.

524

D.

782

Correct option is B

Given:

The areas of the three adjacent faces of a cuboid are:

a × b = 260 cm², b × c = 104 cm², c × a = 10 cm²

Formula Used:

V = a × b × c

Solution:

By multiplying the areas of the three faces:

(a × b) × (b × c) × (c × a) = 260 × 104 × 10

(a² × b² × c²) = 260 × 104 × 10

(a × b × c)² = 260 × 104 × 10

a × b × c = sqrt(260 × 104 × 10)

Volume = 520 cm³

Therefore, the volume of the cuboid is:

Volume = 520 cm³

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