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    The areas of three adjacent faces of a solid cuboid are 127 cm2cm^2cm2​ , 32 cm2cm^2cm2​ and 254 cm2cm^2cm2​ . What is the volume (in c
    Question

    The areas of three adjacent faces of a solid cuboid are 127 cm2cm^2​ , 32 cm2cm^2​ and 254 cm2cm^2​ . What is the volume (in cm3) of thecuboid?

    A.

    941

    B.

    963

    C.

    1163

    D.

    1016

    Correct option is D

    Given:

    Area of three adjacent faces of the cuboid:

    A1 = 127 cm2

    A2 = 32 cm2

    A3 = 254 cm2

    Formula Used:

    Volume of cuboid V = l × b × h

    Area of adjacent faces = l × b, b × h, l × h

    Where, l, b, and h are length, breadth and height

    Solution:

    Multiplying the three areas of the faces:

    (l × b)×(b × h)×(l × h) = 127 × 32 × 254

    (l × b× h)2 = 127 × 32 × 254

    (l × b× h)2 = 1032256

    (l × b× h) = 1032256\sqrt{1032256}​ = 1016cm³

    Thus, the volume of the cuboid is 1016 cm³.

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