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The areas of three adjacent faces of a solid cuboid are 127 cm2cm^2cm2​ , 32 cm2cm^2cm2​ and 254 cm2cm^2cm2​ . What is the volume (in c
Question

The areas of three adjacent faces of a solid cuboid are 127 cm2cm^2​ , 32 cm2cm^2​ and 254 cm2cm^2​ . What is the volume (in cm3) of thecuboid?

A.

941

B.

963

C.

1163

D.

1016

Correct option is D

Given:

Area of three adjacent faces of the cuboid:

A1 = 127 cm2

A2 = 32 cm2

A3 = 254 cm2

Formula Used:

Volume of cuboid V = l × b × h

Area of adjacent faces = l × b, b × h, l × h

Where, l, b, and h are length, breadth and height

Solution:

Multiplying the three areas of the faces:

(l × b)×(b × h)×(l × h) = 127 × 32 × 254

(l × b× h)2 = 127 × 32 × 254

(l × b× h)2 = 1032256

(l × b× h) = 1032256\sqrt{1032256}​ = 1016cm³

Thus, the volume of the cuboid is 1016 cm³.

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