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The area of the circumcircle of a right angle triangle whose sides are given as 8 cm,454\sqrt545​​ cm and 12 cm, is given by ____________.
Question

The area of the circumcircle of a right angle triangle whose sides are given as 8 cm,454\sqrt5 cm and 12 cm, is given by ____________.

A.

9π cm29\textπ\space\text{cm}^2​​

B.

27π cm227\textπ\space\text{cm}^2​​

C.

36π cm236\textπ\space\text{cm}^2​​

D.

18π cm218\textπ\space\text{cm}^2​​

Correct option is C

Given:
Right-angled triangle with sides = 8 cm, 45\sqrt5​ cm, and 12 cm.
Formula Used:
For a right-angled triangle, the hypotenuse is the diameter of the circumcircle.
Radius of circumcircle = Hypotenuse2\dfrac{\text{Hypotenuse}}{2}​​
Area of circumcircle = πr²
Solution:
Here, the longest side = 12 cm i.e. Hypotenuse.
So, Radius r = 122\frac {12}2​ = 6 cm.
Area of circumcircle = π × (6)² = 36π cm².

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