The angle of elevation from a point on the ground, 120 m away from the foot of a tower, is 60° . Find the height of the tower.

Correct option is D

​Given:

Distance from the point to the foot of the tower = 120 m.

Angle of elevation = 60^∘

Formula Used:

$$\tan(\theta) = \frac{\text{height}}{\text{base}} \\ \text{height} = \tan(\theta) \times \text{base}$$​

Solution:

​$$\text{height} = \tan(60^\circ) \times 120 = \sqrt{3} \times 120 = 120 \sqrt3 m$$​​