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Suppose A and B are similar real matrices, that is, there exists an invertible matrix S such that A=SBS−1. A = S B S^{-1}.A=SBS−1.​ Which of the
Question

Suppose A and B are similar real matrices, that is, there exists an invertible matrix S such that A=SBS1. A = S B S^{-1}.
Which of the following need not be true?

A.

Transpose of A is similar to the transpose of B.

B.

The minimal polynomial of A is same as the minimal polynomial of B.

C.

trace(A) = trace(B).

D.

The range of A is the same as range of B.

Correct option is D

Given AB, we know that:ATAandBTB.Thus:ATBT(Statement in Option A is true).\text{Given } A \sim B, \text{ we know that:}\\[10pt]A^T \sim A \quad \text{and} \quad B^T \sim B.\\[10pt]\text{Thus:}\\[10pt]A^T \sim B^T \quad \text{(Statement in Option A is true).}\\[10pt]

​​Since similar matrices have the same eigenvalues, characteristic polynomial, and minimal polynomial:

Statements in Options B and C are also true.

However, the similarity relation does not say anything about the range.

Therange of A may not be equal to the range of B.

Thus, the statement in OptionD need not be true.

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