Study the given diagram and answer the question that follow.

A, B and C are different cities and the given data is of the number of accidents that took place in the respective years 2000, 2005, 2010 and 2015.

Which city has the highest number of accidents on an average?

Correct option is C

Given:

The number of accidents in cities A, B, and C over the years 2000, 2005, 2010, and 2015 is provided in the bar chart.

Formula Used:

$$\text{Average} = \frac{\text{Total number of accidents over years}}{\text{Number of years}}$$​

Solution:

City A:

Total accidents = 400+600+500+550=2050
Average = $$\frac{2050}{4}$$​ = 512.5

City B:

Total accidents = 600+550+350+300=1800
Average = $$\frac{1800}{4}$$​ = 450

City C:

Total accidents = 450+550+650+450=2100
Average = $$\frac{2100}{4}$$​= 525

Since City C has the highest average (525 accidents per year), it has the highest number of accidents on average.

Option (c) is right.