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    Solve the given equation.​3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}4+3×2÷33+4÷2×3​ =​
    Question

    Solve the given equation.

    3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3} =​

    A.

    35\frac{3}{5}​​

    B.

    54\frac{5}{4}​​

    C.

    34\frac{3}{4}​​

    D.

    32\frac{3}{2}​​

    Correct option is D

    Given:

    3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}

    Solution:

    3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}

    =3+2×34+3×23\frac{3+2×3}{4+3×\frac 23}

    =3+64+2\frac{3+6}{4+2}

    =96\frac 96 =32\frac 32​​

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