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Solve the given equation.​3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}4+3×2÷33+4÷2×3​ =​
Question

Solve the given equation.

3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3} =​

A.

35\frac{3}{5}​​

B.

54\frac{5}{4}​​

C.

34\frac{3}{4}​​

D.

32\frac{3}{2}​​

Correct option is D

Given:

3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}

Solution:

3+4÷2×34+3×2÷3\frac{3+4÷2×3}{4+3×2÷3}

=3+2×34+3×23\frac{3+2×3}{4+3×\frac 23}

=3+64+2\frac{3+6}{4+2}

=96\frac 96 =32\frac 32​​

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