​Solve the following.

$$(\frac{2}{7}×\frac{-3}{5}-\frac{1}{12}-\frac{3}{5}×\frac{4}{7})×7$$ ?​

Correct option is C

Given:
​$$(\frac{2}{7}×\frac{-3}{5}-\frac{1}{12}-\frac{3}{5}×\frac{4}{7})×7$$

Concept Used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ^x(power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​
​
Solution:

$$(\frac{2}{7}×\frac{-3}{5}-\frac{1}{12}-\frac{3}{5}×\frac{4}{7})×7\\\ \\=(\frac{-6}{35}-\frac{1}{12}-\frac{12}{35})×7\\\ \\=\frac{(-72 - 35-144)}{420} \times 7 \\\ \\=\frac{-251}{420}\times 7 \\\ \\=\frac{-251}{60}$$​​