Solve the following.

$$25+[20-\lbrace2((20×\frac{1}{5})÷\frac{1}{8}×\frac{1}{16}-8)\rbrace]=$$​ ?​

Correct option is B

Given: 

​$$25+[20-\lbrace2((20×\frac{1}{5})÷\frac{1}{8}×\frac{1}{16}-8)\rbrace]$$ 

Concept Used: ​

​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ^x(power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$ 

Solution: 

​$$25+[20-\lbrace2((20×\frac{1}{5})÷\frac{1}{8}×\frac{1}{16}-8)\rbrace] \\ \ \\ =25+[20-\lbrace2((4)÷\frac{1}{8}×\frac{1}{16}-8)\rbrace] \\ \ \\ = 25+[20-\lbrace2((4)\times {8}×\frac{1}{16}-8)\rbrace]\\ \ \\ = 25+[20-\lbrace2((2-8)\rbrace]\\ \ \\ = 25+[20-\lbrace2(-6)\rbrace]\\ \ \\ = 25+[20+12] \\ \ \\ = 57$$​​