Evaluate: 12×272÷16+2641256÷32−26.25\frac{12\times272\div16+264}{1256\div32-26.25}1256÷32−26.2512×272÷16+264=?
What should replace '?' in the equation given below? 51017÷71234−325=(?)25\frac{10}{17}\div 7\frac{12}{34}-\frac{3}{25}=(?)^251710÷73412−253=(?)2
The value of 55+14−178+7107 \frac{5}{5+\frac{1}{4-\frac{1}{\frac78}}}+\frac{7}{107}5+4−87115+1077 is:
What is the reciprocal of 23\frac{ 2}{3}32?
Which of the following fractions is equivalent to 0.75 ?
The value of (0.29‾÷0.32‾)×6.60.95‾÷1.05‾×1.2‾\frac{(0.\overline{29} \div 0.\overline{32}) \times 6.6}{0.\overline{95} \div 1.\overline{05} \times 1.\overline{2}}0.95÷1.05×1.2(0.29÷0.32)×6.6 is
Value of0.97×0.97×0.97+0.03×0.03×0.030.97×1.94−1.94×0.03+0.03×0.06 \frac{0.97 \times 0.97 \times 0.97 + 0.03 \times 0.03 \times 0.03}{0.97 \times 1.94 - 1.94 \times 0.03 + 0.03 \times 0.06}0.97×1.94−1.94×0.03+0.03×0.060.97×0.97×0.97+0.03×0.03×0.03 is equal to:
4110−[212−{56−(25+310−415)}]4\frac{1}{10}-\left[2\frac{1}{2}-\left\{\frac{5}{6}-\left(\frac{2}{5}+\frac{3}{10}-\frac{4}{15}\right)\right\}\right]4101−[221−{65−(52+103−154)}]on simplification gives
Find the value of [(36÷9)×{568+141×(6−5)}]\left[\left(36 \div 9\right) \times \left\{\frac{56}{8} + \frac{14}{1} \times (6 - 5)\right\}\right][(36÷9)×{856+114×(6−5)}]
The value of 25+(11+57)−25\frac{2}{5}+\left(\frac{1}{1+\frac{5}{7}}\right)-\frac{2}{5}52+(1+751)−52
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