Simplify the following.
$$\frac1{12}+\frac1{16}-\frac18$$​

Correct option is A

Given: 

​$$\frac1{12}+\frac1{16}-\frac18$$ 

Solution: 

= $$\frac1{12}+\frac1{16}-\frac18$$ 

= $$\frac4{48}+\frac3{48}-\frac6{48}$$  

= $$\frac{4+3}{48}-\frac6{48}$$​​

= $$\frac{7-6}{48}$$ 

= $$\frac1{48}$$​​