Correct option is CGiven: s2+t2+2st−u2s2−t2−2tu−u2\frac{ s^2+t^2+2st-u^2}{s^2-t^2-2tu-u^2}s2−t2−2tu−u2s2+t2+2st−u2 s + t + u = 0Formula Used: a2−b2=(a+b)(a−b)a^2-b^2 = (a+b)(a-b)a2−b2=(a+b)(a−b) Solution: