Correct option is DGiven:34÷512−13×95(23÷13−1)\frac{3}{4} \div \frac{5}{12} - \frac{1}{3} \times \frac{9}{5} \left( \frac{2}{3} \div \frac{1}{3} - 1 \right)43÷125−31×59(32÷31−1) Solution:34÷512−13×95(23÷13−1)\frac{3}{4} \div \frac{5}{12} - \frac{1}{3} \times \frac{9}{5} \left( \frac{2}{3} \div \frac{1}{3} - 1 \right)43÷125−31×59(32÷31−1) = 34×125−13×95(23×31−1)\frac{3}{4} \times \frac{12}{5} - \frac{1}{3} \times \frac{9}{5} \left( \frac{2}{3} \times\frac{3}{1} - 1 \right)43×512−31×59(32×13−1) =95−35(2−1)\frac{9}{5}- \frac{3}{5} \left( 2 - 1 \right)59−53(2−1)=6/5