Correct option is AGiven: 11⋅2⋅3+12⋅3⋅4+13⋅4⋅5+14⋅5⋅6\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+\frac{1}{4\cdot5\cdot6}1⋅2⋅31+2⋅3⋅41+3⋅4⋅51+4⋅5⋅61Solution:11⋅2⋅3+12⋅3⋅4+13⋅4⋅5+14⋅5⋅6\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+\frac{1}{4\cdot5\cdot6}1⋅2⋅31+2⋅3⋅41+3⋅4⋅51+4⋅5⋅61= 11×2×3+12×3×4+13×4×5+14×5×6\frac{1}{1\times2\times3}+\frac{1}{2\times3\times4}+\frac{1}{3\times4\times5}+\frac{1}{4\times5\times6}1×2×31+2×3×41+3×4×51+4×5×61= 16+124+160+1120\frac{1}{6}+\frac{1}{24}+\frac{1}{60}+\frac{1}{120}61+241+601+1201= 20+5+2+1120\frac{20+5+2+1}{120}12020+5+2+1= 28120\frac{28}{120}12028= 730\frac{7}{30}307Thus, the correct answer is (a).