Correct option is CGiven: To find : value of (0.1×0.1×0.1+0.2×0.2×0.2)(0.5×0.5×0.5+1) \text{ To find : value of } \frac{(0.1×0.1×0.1+0.2×0.2×0.2)}{(0.5×0.5×0.5+1)} To find : value of (0.5×0.5×0.5+1)(0.1×0.1×0.1+0.2×0.2×0.2) Solution: =(0.1×0.1×0.1+0.2×0.2×0.2)(0.5×0.5×0.5+1) =(0.001+0.008)(0.125+1) =(0.009)(1.125) =1125=0.008= \frac{(0.1×0.1×0.1+0.2×0.2×0.2)}{(0.5×0.5×0.5+1)} \\ \ \\ =\frac{(0.001+0.008)}{(0.125+1)} \\ \ \\ = \frac{(0.009)}{(1.125)} \\ \ \\ = \frac{1}{125} \\ = 0.008=(0.5×0.5×0.5+1)(0.1×0.1×0.1+0.2×0.2×0.2) =(0.125+1)(0.001+0.008) =(1.125)(0.009) =1251=0.008