Set A contains three consecutive multiples of 7, and set B contains five consecutive odd numbers. The largest number in set A is equal to the smallest number in set B. If the average of the smallest number in sets A and B is 28, then find the difference between the 2nd smallest number in set A and the 2nd largest number in set B.

Correct option is C

Let set A number be 7y, 7(y+1) and 7 (y+2)
Let set B number be x, x+2, x+4, x+6 & x+8
ATQ,
7(y+2) = x
x – 7y = 14…(I)
And
(7y+x)/2 = 28
x + 7y = 56….(II)
x = 35
and y = 3
Required difference = 41 - 28 = 13