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    Sachin bought the first pen for ₹630 and the second pen for ₹722, respectively. He sells the first pen at 70% of the profit but the buyer bargain
    Question

    Sachin bought the first pen for ₹630 and the second pen for ₹722, respectively. He sells the first pen at 70% of the profit but the buyer bargains for the price, and he has to offer a 9% discount and the second pen at 71% of the profit. Find the total profit he had in this transaction (correct to two decimal places).​

    A.

    ₹855.49

    B.

    ₹857.23

    C.

    ₹856.32

    D.

    ₹854.79

    Correct option is B

    Given:

    CP₁ (first pen) = ₹630; intended profit = 70%, but a discount of 9% is offered on the marked price.

    CP₂ (second pen) = ₹722; sold at 71% profit.

    Find total profit (₹), correct to two decimals.

    Formula Used:

    Marked Price for p% profit:

    MP=CP×(1+p/100)\text{MP} = \text{CP} \times (1+p/100) ​​

    Discount d% on MP

    SP=MP×(1d/100)\text{SP} = \text{MP} \times (1-d/100) ​​

    Profit = SP − CP;

    Profit% =SPCPCP×100 \dfrac{\text{SP}-\text{CP}}{\text{CP}}\times 100​​

    Solution:
    First pen:
    MP1=630×1.70=1071\text{MP}_1 = 630 \times 1.70 = 1071​​
    SP1=1071×0.91=974.61\text{SP}_1 = 1071 \times 0.91 = 974.61​​
    Profit1=974.61630=344.61\text{Profit}_1 = 974.61 - 630 = 344.61​​

    Second pen:
    SP2=722×1.71=1234.62\text{SP}_2 = 722 \times 1.71 = 1234.62​​
    Profit2=1234.62722=512.62\text{Profit}_2 = 1234.62 - 722 = 512.62​​

    Profittotal=344.61+512.62=857.23\text{Profit}_{\text{total}} = 344.61 + 512.62 = ₹857.23​​

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