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Ravi and Sanju together can do a job in 2 days, Sanju and Mahesh can do it in 4 days, while Ravi and Mahesh can do it in 2 days. What is the number of
Question

Ravi and Sanju together can do a job in 2 days, Sanju and Mahesh can do it in 4 days, while Ravi and Mahesh can do it in 2 days. What is the number of days required for Ravi to do the same job alone?

A.

4 days

B.

83\frac{8}{3}​ days

C.

53\frac{5}{3} days

D.

9 days

Correct option is B

Given:
Ravi and Sanju together can complete the job in 2 days.
Sanju and Mahesh together can complete the job in 4 days.
Ravi and Mahesh together can complete the job in 2 days.

Formula Used:

Total Work = Efficiency ×\times Total Time

Solution:

LCM (2, 4, 2) = 4

2 (Ravi + Sanju + Mahesh) = 5

Efficiency of (Ravi + Sanju + Mahesh) = 52=2.5\frac{5}{2} = 2.5

So, Ravi = 1.5, Sanju = 0.5 , Mahesh = 0.5

The time required for Ravi to complete the job alone = 41.5=4015=83\frac{4}{1.5} = \frac{40}{15} = \frac{8}{3} days

Thus, the correct option is (b)

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