Given:
A, B, and C can do the work on their own in 5, 10, and 15 days respectively.
Solution:
Total work = LCM of 5, 10, and 15= 30 units
Efficiency of B = = 3 unit work in 1 day
Efficiency of C = = 2 unit work in 1 day
Efficiency of B and C together = (3 + 2) = 5 unit work in 1 day
Time taken to complete the work by B and C = = 6 days.
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