Rationalising factor of $$\sqrt[3]{40}$$​ is:

Correct option is B

Given:
The expression: $$\sqrt[3]{40}$$​​
Solution:
40 =$$8 \times 5 = 2^3 \times 5$$​​
​$$\sqrt[3]{40} = \sqrt[3]{2^3 \times 5} = 2 \times \sqrt[3]{5}$$​​
Rationalizing factor
To rationalize $$\sqrt[3]{5}$$​, multiply it by $$\sqrt[3]{5^2}$$​ (since $$5 \times 5^2 = 5^3 = 125$$​, a perfect cube).
Rationalizing factor = $$\sqrt[3]{5^2} = 5^\frac 23$$​