Find the value of $$\left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{7}\right)^{-2}$$​​

Correct option is B

Given:

​$$\left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{7}\right)^{-2}$$ 

Solution: ​

​$$\left(\frac{1}{4}\right)^{-2} + \left(\frac{1}{9}\right)^{-2} + \left(\frac{1}{7}\right)^{-2} \\ \ \\ = \left({4}\right)^{2} + \left({9}\right)^{2} + \left({7}\right)^{2} \\ \ \\ = 16 + 81 + 49 \\ \ \\ = 146$$​​