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Rajni can do 25% less work than Mohan and Mohan can do 20% more work than Rizwan. At the end of the completion of the work, what will be Mohan’s share
Question

Rajni can do 25% less work than Mohan and Mohan can do 20% more work than Rizwan. At the end of the completion of the work, what will be Mohan’s share out of the profit of Rs. 930?

A.

Rs. 350

B.

Rs. 360

C.

Rs. 300

D.

Rs. 260

Correct option is B

Given:

Rajni can do 25% less work than Mohan.

Mohan can do 20% more work than Rizwan.

Solution:
Let the amount of work done by Rizwan be R units.

Mohan can do 20% more work than Rizwan.

So, the work done by Mohan is:
Work by Mohan} = R + 0.2R = 1.2R

Rajni can do 25% less work than Mohan.

So, the work done by Rajni is:

Work by Rajni = 1.2R0.25×1.2R=0.75×1.2R=0.9R1.2R - 0.25 \times 1.2R = 0.75 \times 1.2R = 0.9R​​

The total work done by Rajni, Mohan, and Rizwan is:
Total work= 0.9R + 1.2R + R = 3.1R

Mohan’s share of the profit

Mohan’s share =Work by MohanTotal work×Total profit \frac{\text{Work by Mohan}}{\text{Total work}} \times \text{Total profit}​​

Mohan’s share =1.2R3.1R×930=1.23.1×930 \frac{1.2R}{3.1R} \times 930 = \frac{1.2}{3.1} \times 930​​

                                         = 1.2×9303.1=11163.1\frac{1.2 \times 930}{3.1} = \frac{1116}{3.1}​​
Thus, Mohan’s share of the profit is:Rs.360


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