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Rajeev starts from A to B at 6:00 AM at a speed of 60 km/hr. After 2 hours, Suresh starts from B towards A at a speed of 80 km/hr. The distance betwee
Question

Rajeev starts from A to B at 6:00 AM at a speed of 60 km/hr. After 2 hours, Suresh starts from B towards A at a speed of 80 km/hr. The distance between A and B is 750 km. At what time will they meet?

A.

1:30 PM

B.

1:00 PM

C.

12:30 PM

D.

2:00 PM

Correct option is C

Given:
Speed of Rajeev = 60 km/hr
Speed of Suresh = 80 km/hr
Total distance between A and B = 750 km
Rajeev's start time = 6:00 AM
Suresh's start time = 8:00 AM (2 hours after Rajeev)
Formula Used:
Distance = Speed × Time
Relative Speed (opposite directions) = Speed{1} + Speed{2}
Time to meet = Remaining DistanceRelative Speed\frac{Remaining\ Distance}{Relative\ Speed}​​
Solution:
First, find the distance covered by Rajeev in the first 2 hours (from 6:00 AM to 8:00 AM):
Distance = 60 × 2 = 120 km
Now, calculate the remaining distance between them at 8:00 AM:
Remaining Distance = 750 - 120 = 630 km
Calculate their relative speed as they are moving towards each other:
Relative Speed = 60 + 80 = 140 km/hr
Find the time taken to cover the remaining distance:
Time taken = 630140\frac{630}{140}​​
Time taken = 4.5 hours
This means they will meet 4.5 hours after 8:00 AM.
4.5 hours is equal to 4 hours and 30 minutes.
8:00 AM + 4 hours 30 minutes = 12:30 PM.
Final Answer
So the correct answer is (c)

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