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    A 145 m long train crosses a man walking at a speed of 9.5 km/h in the opposite direction in 30 seconds. What is the speed (in km/h) of the train ?
    Question

    A 145 m long train crosses a man walking at a speed of 9.5 km/h in the opposite direction in 30 seconds. What is the speed (in km/h) of the train ?

    A.

    4.4

    B.

    7.9

    C.

    6.1

    D.

    7.5

    Correct option is B

    Given:

    Length of train = 145 m

    Speed of man = 9.5 km/h (opposite direction)

    Time to cross = 30 seconds

    Find: Speed of train (in km/h)

    Formula Used:

    Relative Speed = Distance / Time

    Train Speed = Relative Speed − Man Speed (since opposite direction → relative = train + man)

    145 m = 0.145 km

    30 sec = 303600\frac{30}{3600}​ = 1120 \frac1{120}​ hour

    Solution:

    Relative Speed = 0.145 ÷ 1120\frac1{120}​ = 0.145 × 120 = 17.4 km/h

    Train Speed = 17.4 - 9.5 = 7.9 km/h

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