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    Radhika requested the cashier of a bank to get her coins in lieu of her cheque worth Rs. 1,845. Cashier gave her a packet containing Rs. 5, Rs. 10 and
    Question

    Radhika requested the cashier of a bank to get her coins in lieu of her cheque worth Rs. 1,845. Cashier gave her a packet containing Rs. 5, Rs. 10 and Rs. 20 coins in the ratio of 3: 5:7. What is the total worth of the smallest coin received by her?

    A.

    Rs. 125

    B.

    Rs. 105

    C.

    Rs. 145

    D.

    Rs. 135

    Correct option is D

    Given:
    Total money – Rs. 1845
    Coins = Rs. 5, Rs. 10 and Rs. 20
    Ratio = 3: 5:7
    Solution:
    Let the number of Rs. 5, Rs. 10 and Rs. 20 be 3x, 5x and 7x
    The total no of coins = 3x + 5x + 7x = 15x ……….(1)
    Now the amount of Rs. 5, Rs. 10 and Rs. 20 coins will be 15x, 50x and 140x respectively.
    Total amount = 15x + 50x + 140x = 205x
    According to the question,
    205x = 1845
    x = 1845205\frac{1845}{205}​​
    x = 9
    The total worth of the smallest coin received by her = 15x = 15 × 9 = 135.

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