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Pravin has Rs. 1612 with him. He divided it amongst his sons Rishi and Shan and asked them to invest it at 8% rate of interest compounded annually. It
Question

Pravin has Rs. 1612 with him. He divided it amongst his sons Rishi and Shan and asked them to invest it at 8% rate of interest compounded annually. It was seen that Rishi and Shan got same amount after 17 and 18 years respectively. How much (in Rs. ) did Pravin give to Rishi?

A.

687

B.

775

C.

875

D.

837

Correct option is D

Given:

Total amount Pravin has: ₹1612

Rishi invests for 17 years, and Shan invests for 18 years at a 8% annual compound interest rate.

Formula Used:

The formula for compound interest is:

A=P(1+r100)tA = P \left( 1 + \frac{r}{100} \right)^t​​

Where:

A is the amount after t years,

P is the principal (initial amount),

r is the rate of interest 

t is the time in years.

Solution:

Let the amount given to Rishi beP1P_1 and the amount given to Shan beP2P_2​. Therefore, 

P1+P2=1612P_1 + P_2 = 1612​​

For Rishi 

A1=P1(1+8100)17=P1×1.0817A_1 = P_1 \left( 1 + \frac{8}{100} \right)^{17} = P_1 \times 1.08^{17}​​

For Shan

A2=P2(1+8100)18=P2×1.0818A_2 = P_2 \left( 1 + \frac{8}{100} \right)^{18} = P_2 \times 1.08^{18}​​

Given that A1=A2:A_1 = A_2:​​

P1×1.0817=P2×1.0818P_1 \times 1.08^{17} = P_2 \times 1.08^{18}​​

P1=P2×1.08181.0817=P2×1.08P_1 = P_2 \times \frac{1.08^{18}}{1.08^{17}} = P_2 \times 1.08​​

P1=1.08×P2P_1 = 1.08 \times P_2​​

Substituting P1=1.08×P2P_1 = 1.08 \times P_2​ into P1+P2=1612: P_1 + P_2 = 1612:​​

1.08×P2+P2=16121.08 \times P_2 + P_2 = 1612​​

P2=16122.08=775P_2 = \frac{1612}{2.08} = 775​​

Now,

P1=1.08×775=837P_1 = 1.08 \times 775 = 837​​

Thus, Pravin gave ₹837 to Rishi

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