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∆PQR and ∆SQR are both isosceles triangles on a common base QR such that P and S lie on the same side of QR. If ∠QSR = 60° and ∠QPR= 100°, then find ∠
Question

∆PQR and ∆SQR are both isosceles triangles on a common base QR such that P and S lie on the same side of QR. If ∠QSR = 60° and ∠QPR= 100°, then find ∠SRP

A.

80°

B.

60°

C.

100°

D.

20°

Correct option is D

We know PR = PQ and SR = SQ
∠QPR = 100°
∠QPR + ∠PQR + ∠PRQ = 180°
∠QPR + ∠PQR + ∠PQR = 180°
100+∠PQR + ∠PQR= 180°
∠PQR = 40° and ∠PRQ = 40°
Similarly, if ∠QSR = 60° then ∠SQR = 60° and ∠SRQ = 60°
∠SRP = ∠SRQ - ∠PRQ
∠SRP = 60 - 40 = 20°

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