PQ is the diameter of a circle whose centre is O. if a point R lies on the circle and ∠RPO is 39°, then what will be the measure of ∠RQP?

Correct option is A

Given:

PQ is the diameter of the circle, and O is the center of the circle.

Point R lies on the circle.

∠RPO = $$39^\circ$$​.

Concept Used:

The angle subtended by a diameter of a circle at the circumference is a right angle, i.e., ∠PRQ = 90$$^\circ$$​​

​Solution:

In △POR ∠RPO=39$$^\circ$$​

∠RQP+∠RPO+ ∠PRQ = 180

∠RQP+ 39 + 90 = 180

∠RQP = 180 – 129

∠RQP = 51$$^\circ$$​​