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PQ is a diameter of circle whose centre is O. If a point R lies on a circle and ∠RPO is 42°, then find ∠RQP.
Question

PQ is a diameter of circle whose centre is O. If a point R lies on a circle and ∠RPO is 42°, then find ∠RQP.

A.

29°

B.

48°

C.

51°

D.

25°

Correct option is B

Given:

PQ is the diameter of the circle with center O

∠RPO = 42°

Point R lies on the circle

Concept Used:

In a circle:

Angle subtended by a diameter at the circumference is a right angle (i.e., ∠R = 90°)

Sum of interior angles of triangle = 180°

Solution:

RQP=180(42+90)=180132=48\angle RQP = 180^\circ - (42^\circ + 90^\circ) = 180^\circ - 132^\circ = 48^\circ

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