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    PQ is a diameter of circle whose centre is O. If a point R lies on a circle and ∠RPO is 42°, then find ∠RQP.
    Question

    PQ is a diameter of circle whose centre is O. If a point R lies on a circle and ∠RPO is 42°, then find ∠RQP.

    A.

    29°

    B.

    48°

    C.

    51°

    D.

    25°

    Correct option is B

    Given:

    PQ is the diameter of the circle with center O

    ∠RPO = 42°

    Point R lies on the circle

    Concept Used:

    In a circle:

    Angle subtended by a diameter at the circumference is a right angle (i.e., ∠R = 90°)

    Sum of interior angles of triangle = 180°

    Solution:

    RQP=180(42+90)=180132=48\angle RQP = 180^\circ - (42^\circ + 90^\circ) = 180^\circ - 132^\circ = 48^\circ

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