Correct option is A
Given:
PQ is diameter.
∠RPQ = 27°
AR is tangent,
Concept Used:
Triangle in a circle made by the its diameter is right angle triangle.
Solution:

∠PRQ = 90°
In Right Angle triangle ∆PRQ
∠R+∠P+∠Q = 180°
90° + 27° + ∠Q = 180°
∠Q = 180° - (90° + 27°)
∠Q = 180° - 117°
∠Q = 63°
