On a one-way road, broken lines consisting of 2.5 m length segments separated by 2.5 m gaps are painted along the length of the road to demarcate 3 lanes, and continuous lines are painted along both the borders. What is the total length of the painted lines (in m) over a 250 m stretch of the road?

Given:-

Length of the road = 250 m
Length of each segment of broken lines = 2.5 m
Gap between segments = 2.5 m
Number of lanes = 3
Continuous lines along both borders.

Length of each broken line segment = 2.5 m, and the gap between them is also 2.5 m.
Each unit of broken line is 2.5 m (line) + 2.5 m (gap) = 5 m.
For 250 m of road, the number of units of broken lines =  $$\frac {250}{5}=50$$ 

Since there are 3 lanes,  for 2 broken lines (one for the first lane and one for the second lane).

Total length of broken lines = $$50 \times 2.5 \times 2 = 250$$ m

Continuous lines are painted on both borders of the road, so we have 2 continuous lines.
Total length of continuous lines = $$250 \times 2 =500$$ m

Total Length of Painted Lines:
250m (broken lines) + 500m (continuous lines) = 750m

Thus, the correct answer is (C) 750