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    O is the centre of a circle and A is a point on a major arc BC of the circle. ∠BOC and ∠BAC are the angles made by the minor arc BC on the centre and
    Question

    O is the centre of a circle and A is a point on a major arc BC of the circle. ∠BOC and ∠BAC are the angles made by the minor arc BC on the centre and circumference, respectively. If ∠ABO = 40° and ∠ACO = 30°, then find ∠BOC.

    A.

    130°

    B.

    140°

    C.

    120°

    D.

    150°

    Correct option is B

    ∠ABO = ∠OAB= 40°  (opposite angles of the equal sides are equal)
    ∠ACO = ∠OAC = 30°  (opposite angles of the equal sides are equal)
    ∠BAC = 40 + 30 = 70°
    Angle made on centre is two times angle made on circumference by the same arc.
    ∠BOC = 2 × 70 = 140°

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