Match List I with List II

List I	List II
A. Z Score	I. X̄ = 50, σ = 10
B. Stanine	II. X̄ = 5.5, σ = 2
C. T Score	III. X̄ = 5, σ = 2 (approx)
D. Sten	IV. X̄ = 0, σ = 1

Correct option is A

The correct answer is (1).
1. Z Score (A): The Z Score is calculated by subtracting the mean (X̄) and dividing by the standard deviation (σ). It typically uses a mean of 0 and a standard deviation of 1. Hence, A - IV.
2. Stanine (B): Stanine is a scoring scale with a mean of 5.5 and a standard deviation of 2. Hence, B - III.
3. T Score (C): A T Score has a mean of 50 and a standard deviation of 10. Hence, C - I.
4. Sten (D): Sten scores have a mean of 5 and a standard deviation of approximately 2. Hence, D - II.

Information Booster

Common Scoring Systems

1.1 Z Score:
The Z Score represents how many standard deviations a data point is from the mean. It is calculated as: Z=X−XˉσZ = \frac{X - X̄}{σ}
A Z Score with a mean of 0 and a standard deviation of 1 is commonly used in standardized tests and normal distribution analyses.

1.2 Stanine:
The Stanine scale ranges from 1 to 9, with 5 as the mean. It divides the data into nine equal parts and assigns a standard deviation of 2. It is often used for academic testing and gives a broad but effective measure of a person’s performance in a specific area.

1.3 T Score:
A T Score has a mean of 50 and a standard deviation of 10. It is used in psychological testing and other assessments where it’s important to have scores that are easy to compare across different scales or groups. The T Score is generally used in personality and clinical assessments.

1.4 Sten:
The Sten scale, used in psychological assessments, ranges from 1 to 10 and has a mean of 5 with a standard deviation of about 2. It is commonly used in IQ testing and other measures of intelligence or aptitude.