Let 2a 3b 5c = 1200 where a, b, c are integers. Then a + 2b + 3c is
Given:
2a × 3b × 5c = 1200
Solution:
Factorize 1200: 1200 = 2⁴ × 3¹ × 5²
Now compare the exponents of prime factors with the given equation: a = 4, b = 1, c = 2
Formula to find: a + 2b + 3c
Substitute the values: a + 2b + 3c = 4 + 2(1) + 3(2) = 4 + 2 + 6 = 12
Thus, the answer is 12.
Simplify x(5x − 9) + 7(x2 − 2) + 17
Simplify .
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Find x in the following expression:
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Simplify: .
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