Correct option is DGiven: 2((62)x2−22x+15)−6(x2+5x−18)2\left(\left(\frac{6}{2}\right)x^2-22x+15\right)-6(x^2+5x-18)2((26)x2−22x+15)−6(x2+5x−18) Solution: 2((62)x2−22x+15)−6(x2+5x−18) =6x2−44x+30−6x2−30x+108 =−74x+1382\left(\left(\frac{6}{2}\right)x^2-22x+15\right)-6(x^2+5x-18) \\ \ \\ = 6x^2-44x+30-6x^2-30x+108 \\ \ \\ = -74x+1382((26)x2−22x+15)−6(x2+5x−18) =6x2−44x+30−6x2−30x+108 =−74x+138