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Krishna has a few coins of 1 rupee, 50 paise and 25 paise in the ratio 14:12:12\frac14:\frac12:\frac1241​:21​:21​​. If the number of 25 paise coins is
Question

Krishna has a few coins of 1 rupee, 50 paise and 25 paise in the ratio 14:12:12\frac14:\frac12:\frac12​. If the number of 25 paise coins is 100 , then the total amount with Krishna is:

A.

Rs. 100

B.

Rs. 75

C.

Rs. 125

D.

Rs. 120

Correct option is C

Given:

The ratio of 1 rupee : 50 paise : 25 paise coins is 14:12:12 \frac{1}{4} : \frac{1}{2} : \frac{1}{2} 

the number of 25 paise coins is 100

Solution:

Given ratio is 14:12:12 \frac{1}{4} : \frac{1}{2} : \frac{1}{2} This simplifies to: 1:2:21:2:2 

​Let the number of 1 rupee coins be xxx, the number of 50 paise coins be 2x2x2x, and the number of 25 paise coins be 2x2x2x.

​the number of 25 paise coins is 100. So, 2x=1002x = 1002x=100 

x = 50 

Number of 1 rupee coins = x=50x = 50x=50

​Number of 50 paise coins = 2x=1002x = 1002x=100

​Number of 25 paise coins = 2x=1002x = 1002x=100

now, value of coins

Value of 1 rupee coins: 50×1=5050 \times 1 = 5050×1=50 rupees

​Value of 50 paise coins: 100×0.50=50100 \times 0.50 = 50100×0.50=50 rupees

Value of 25 paise coins: 100×0.25=25100 \times 0.25 = 25100×0.25=25 rupees

​sum of the values: 50 + 50 + 25 = 125 rupees

Thus, the total amount with Krishna is 125 rupees.​

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