Correct option is A
Explanation-
Statement A - PCR is followed by transformation of bacterial cells directly with the reaction mixture. A large number of the transformants will have the wild type gene. - CORRECT
Without DpnI treatment, the parental (wild-type) plasmid is still present and will be efficiently transformed, leading to a high number of wild-type transformants.
Statement B - The PCR mixture is treated with DpnI and then used to transform bacterial cells. Most of the transformants will have the mutant gene. - CORRECT
DpnI digests the methylated (parental) DNA. The mutant PCR product (newly synthesized and unmethylated) remains and transforms the bacteria, resulting in mostly mutant colonies.
Statement C - PCR is followed by transformation of bacterial cells directly with the reaction mixture. None of the transformants will have the mutant gene. - INCORRECT
Even without DpnI, some mutant plasmids can be taken up, although the majority will be wild type. So saying none is too absolute.
Statement D - The PCR mixture is treated with DpnI and then used to transform bacterial cells. Half of the transformants will have the mutant gene. - INCORRECT
After DpnI treatment, the majority (not just half) of transformants will have the mutant plasmid, as the wild-type is degraded.
Correct Answer: Option a - A and B