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    A. 5'- AGTAGTATCAACTATCATGA-3' 3'- TCATCATAGTTGATAGTACT-5'B. 5'- GACGTGCAGGTGCGGAGGTC-3' 3'- CTGCACGGTCCACCTCCAG-5'C. 5'- TACGATGCACATGCTTGGA-3' 3'- A
    Question

    A.
    5'- AGTAGTATCAACTATCATGA-3'
    3'- TCATCATAGTTGATAGTACT-5'

    B.
    5'- GACGTGCAGGTGCGGAGGTC-3'
    3'- CTGCACGGTCCACCTCCAG-5'

    C.
    5'- TACGATGCACATGCTTGGA-3'
    3'- ATGCTACGTGTACGAACCTG-5'

    D.
    5'- GAACGCTACGTTGCGATCCG-3'
    3'- CTTGCATGCAACGCTAGGC-5'

    Arrange the DNA fragments (A to D) in the order of decreasing melting temperature.

    A.

    B>D>C>A

    B.

    C>A>B>D

    C.

    D>C>A=B

    D.

    A=B>C>D

    Correct option is A

    Explanation-

    G≡C base pairs have 3 hydrogen bonds → more stable
    A=T base pairs have 2 hydrogen bonds
    Higher GC content = higher melting temperature (Tm)

    Step-by-Step GC Content Calculation:
    Fragment A: Sequence: AGTAGTATCAACTATCATGA
    Length = 20 bases
    G count = 2
    C count = 2
    GC content = 4/20 = 20%
    Fragment B: Sequence: GACGTGCCAGGTGCGAGGTC
    Length = 20 bases
    G count = 8
    C count = 6
    GC content = 14/20 = 70%
    Fragment C: Sequence: TACGATGCACATGCTTGGAC
    Length = 20 bases
    G count = 5
    C count = 5
    GC content = 10/20 = 50%
    Fragment D: Sequence: GAACGCTACGTTGCGATCCG
    Length = 20 bases
    G count = 6
    C count = 6
    GC content = 12/20 = 60%

    Final Order Based on GC Content (Decreasing Tm):
    B → 70% GC
    D → 60% GC
    C → 50% GC
    A → 20% GC

    Correct Order: B > D > C > A (Option a)

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