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    #include<stdio.h> void main() { int arr[] = {1, 2, 3, 4, 5}; int *p = arr; printf("%d", *p++); printf("%d", *(p + 1));
    Question




    #include<stdio.h>
    void main()
    {
    int arr[] = {1, 2, 3, 4, 5};
    int *p = arr;
    printf("%d", *p++);
    printf("%d", *(p + 1));
    }
    Find the output of the above code?

    A.

    1, 2

    B.

    1, 3

    C.

    2, 3

    D.

    1, 4

    Correct option is B


    1. Pointer Operations:
    · int *p = arr; initializes p to point to the first element of arr.
    · *p++ evaluates *p (value at arr[0], which is 1), then increments p to point to arr[1].
    2. Second Print Statement:
    · *(p + 1) now refers to arr[2], which has a value of 3.
    Information Booster:
    · *p++: This increments the pointer after dereferencing.
    · Pointer arithmetic is used to move to the next element in memory.

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