Consider following C program:
#include <stdio.h>
int main()
{
int x[] = {2, 4, 6, 8, 10};
int a, b = 0, *y = x + 4;
for (a = 0; a < 5; a++)
{
b = b + (*y - a) - *(y - a);
}
printf("%d\n", b);
return 0;
}
What will be the output of the above C program?

Correct option is D

1. The pointer y points to x + 4, which is x[4] (value 10).
2. In each iteration, the expression (*y - a) - *(y - a) is evaluated.
· a = 0: b = b + (10 - 0) - 10 = 0
· a = 1: b = b + (10 - 1) - 8 = 1
· This results in b = 10 after the loop.
Information Booster:
Pointers: Useful for accessing and manipulating elements of an array efficiently.