In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.

Number/Symbol

5

4

+

@

?

3

<

#

2

%

!

9

=

6

Code

B

S

R

T

U

P

D

Y

A

V

C

X

E

H

Conditions:

(i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.
(ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as ∅.

(iii) If both second and third elements are either symbols or numbers, the third element is to be coded as the code for the second element.
How will ' 5%=3 ! 9 ' be coded? ​​

Given code: ' 5%=3 ! 9 ' 

​Apply Condition (i):

If the first element is a symbol and the last, a number, the codes for these two are to be interchanged. (Not applicable here since the first element is a number).

​Apply Condition (ii):

​If the first element is an odd number and the last, an even number, the first and last elements are to be coded as ∅. (Not applicable here since the last element is an odd number).

​Apply Condition (iii):

​If both second and third elements are either symbols or numbers, the third element is to be coded as the code for the second element.

Here, the second element (%) and third element (=) are symbols, so the third element (=) should be coded as the second element (%).

Coding the Sequence:

5 = B

%= V

= = V (third element (=) should be coded as the second element (%))

3 = P

! = C

9= X

So, ' 5%=3 ! 9 '  is coded as BVVPCX

Thus, correct option is (b)​​