Correct option is A
Given:
Number/Symbol | 4 | # | $ | + | 7 | 9 | 2 | 6 | @ | 3 | & | 5 |
Code | B | W | Q | E | C | A | T | J | N | P | D | G |
Conditions:
(i) If the first element is a number and the last element is a symbol, then the codes for the first and last elements are to be interchanged.
True, first element is a number and the last element is a symbol, then the codes for the first and last elements are to be interchanged. So, the code is E 6 # 4 G.
(ii) If the first element is divisible by 2 and the last element is divisible by 3, then the first and last elements are to be coded as *. False
(ii) If the first element is divisible by 2 and the last element is divisible by 3, then the first and last elements are to be coded as *. False
(iii) If the first element is a symbol and the last element is an even number, then their codes (i.e. first and last element) are to be changed to the code for 3. False
So, the code of 56#4+ is EJWBG.
Thus, correct option is (a).
