In the following decomposition reaction, identify the p q r s:

$$p FeSO_4(s) \rightarrow q Fe_2O_3(s) + rSO_2(g) + sSO_3(g)$$​​
​

Correct option is D

Given reaction:

FeSO4(s)→Fe2O3(s)+SO2(g)+SO3(g)\text{FeSO}_4 (s) \rightarrow \text{Fe}_2\text{O}_3 (s) + \text{SO}_2 (g) + \text{SO}_3 (g)FeSO4​(s)→Fe2​O3​(s)+SO2​(g)+SO3​(g)

Step-by-step balancing:

1. Balance the iron atoms:

   • On the left side, there is 1 Fe atom (in FeSO₄).
   • On the right side, Fe is present in Fe₂O₃, where there are 2 Fe atoms.
   • To balance Fe, put a coefficient of 2 in front of FeSO₄ on the left side:2FeSO4→Fe2O3+SO2+SO32 \text{FeSO}_4 \rightarrow \text{Fe}_2\text{O}_3 + \text{SO}_2 + \text{SO}_32FeSO4​→Fe2​O3​+SO2​+SO3​

2. Balance the sulfur atoms:

   • On the left side, there are 2 sulfur atoms (in 2 FeSO₄).
   • On the right side, sulfur is present in SO₂ and SO₃.
   • Put a coefficient of 2 in front of SO₂ to balance sulfur:2FeSO4→Fe2O3+2SO2+SO32 \text{FeSO}_4 \rightarrow \text{Fe}_2\text{O}_3 + 2 \text{SO}_2 + \text{SO}_32FeSO4​→Fe2​O3​+2SO2​+SO3​

3. Balance oxygen atoms:

   • On the left side, there are 8 oxygen atoms (in 2 FeSO₄).
   • On the right side:
     • Fe₂O₃ has 3 oxygen atoms.
     • 2 SO₂ has 4 oxygen atoms.
     • SO₃ has 3 oxygen atoms.
   • Total oxygen atoms on the right side = 3 (from Fe₂O₃) + 4 (from 2 SO₂) + 3 (from SO₃) = 10.
   • Therefore, to balance oxygen, we add a coefficient of 1 in front of SO₃:2FeSO4→Fe2O3+2SO2+SO32 \text{FeSO}_4 \rightarrow \text{Fe}_2\text{O}_3 + 2 \text{SO}_2 + \text{SO}_32FeSO4​→Fe2​O3​+2SO2​+SO3​

Thus, the correct set of values for p, q, r, s is:

• p = 2 (for FeSO₄)
• q = 1 (for Fe₂O₃)
• r = 2 (for SO₂)
• s = 1 (for SO₃)

So the correct answer is (D) 2, 1, 1, 1.