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In right-angled triangle ABC, ∠C=90, CM is perpendicular on AB. If AB = 18 cm and BM = 6 cm, then find the length of CM.
Question

In right-angled triangle ABC, ∠C=90, CM is perpendicular on AB. If AB = 18 cm and BM = 6 cm, then find the length of CM.

A.

62 cm6\sqrt2\space\text{cm}​​

B.

42 cm4\sqrt2\space\text{cm}​​

C.

72 cm7\sqrt2\space\text{cm}​​

D.

22 cm2\sqrt2\space\text{cm}​​

Correct option is A

Given:

Triangle ABC is a right-angled triangle with ∠C = 90°.

CM is perpendicular to AB.

AB = 18 cm, BM = 6 cm.

Formula Used:

CM2^2​ = BM ×\times​ AM
AM = AB − BM

Solution:

AB = 18 cm, BM = 6 cm, so AM=18−6=12 cm

Apply the altitude-on-hypotenuse theorem:

CM2^2​ = BM ×\times ​AM = 6 ×\times ​12 = 72

CM = 72=62 cm\sqrt{72} = 6\sqrt{2} \, \text{cm}​​

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