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    In right-angled triangle ABC, ∠C=90, CM is perpendicular on AB. If AB = 18 cm and BM = 6 cm, then find the length of CM.
    Question

    In right-angled triangle ABC, ∠C=90, CM is perpendicular on AB. If AB = 18 cm and BM = 6 cm, then find the length of CM.

    A.

    62 cm6\sqrt2\space\text{cm}​​

    B.

    42 cm4\sqrt2\space\text{cm}​​

    C.

    72 cm7\sqrt2\space\text{cm}​​

    D.

    22 cm2\sqrt2\space\text{cm}​​

    Correct option is A

    Given:

    Triangle ABC is a right-angled triangle with ∠C = 90°.

    CM is perpendicular to AB.

    AB = 18 cm, BM = 6 cm.

    Formula Used:

    CM2^2​ = BM ×\times​ AM
    AM = AB − BM

    Solution:

    AB = 18 cm, BM = 6 cm, so AM=18−6=12 cm

    Apply the altitude-on-hypotenuse theorem:

    CM2^2​ = BM ×\times ​AM = 6 ×\times ​12 = 72

    CM = 72=62 cm\sqrt{72} = 6\sqrt{2} \, \text{cm}​​

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