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    In quadrilateral PQRS, the bisectors of ∠R and ∠S meet at point T (inside the quadrilateral) and ∠STR = 32.5°. If the ratio of ∠P to ∠Q is 4 : 9,
    Question

    In quadrilateral PQRS, the bisectors of ∠R and ∠S meet at point T (inside the quadrilateral) and ∠STR = 32.5°. If the ratio of ∠P to ∠Q is 4 : 9, then what is the difference between the measures of ∠Q and ∠P?​

    A.

    27°

    B.

    24°

    C.

    25°

    D.

    28°

    Correct option is C

    Given:

    ∠STR = 32.5

    Ratio of ∠P : ∠Q = 4 : 9

    T is the point of intersection of angle bisectors of ∠R and ∠S

    Solution: 

    In STR\triangle STR 

    12PSR+12QRS+STR=180° 12PSR+12QRS=180°32.5=147.5°  PSR+QRS=147.5°×2=295°\frac12\angle PSR+\frac12\angle QRS +\angle STR = 180 \degree \\ \ \\ \frac12\angle PSR+\frac12\angle QRS = 180 \degree - 32.5 = 147.5\degree \\ \ \\ \implies \angle PSR+\angle QRS = 147.5\degree \times 2 = 295\degree  

    Now, In quadrilateral PQRS 

    PSR+QRS+RQS+QPS=360° 295°+4x+9x=360° 13x=360295=65° x=5°\angle PSR + \angle QRS +\angle RQS +\angle QPS = 360\degree \\ \ \\ 295\degree + 4x+9x = 360\degree \\ \ \\ 13x = 360-295 = 65\degree \\ \ \\ x = 5\degree

    Now,  ∠Q - ∠P  = 9x - 4x = 5x = 5×5=25°5\times 5 = 25\degree​​​

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