In how many years will a sum of money be 12 times itself at 44% per annum simple interest?

Correct option is B

Given:

Final amount = 12 times the principal

Rate (R) = 44% per annum

Simple Interest (SI)

Formula Used:

A = P + SI

SI = $$\frac{P \times R \times T}{100}$$​​

Solution:

A = 12 P

=>12P = P + SI

=>SI = 11P

11P = $$\frac{P \times 44 \times T}{100}$$​​

11 = $$\frac{44T}{100}$$​​

$$\Rightarrow$$​ 1100 = 44T

​$$\Rightarrow T = \frac{1100}{44}$$​​

= 25 years

Thus, the correct option is (b) 25 years