In given figure OP||RS, ∠OPQ = 100° and ∠QRS = 140°, then ∠PQR is equal to

Correct option is B

Given figure OP||RS, ∠OPQ = 100° and ∠QRS = 140°, then ∠PQR is equal to

we extend of ray O and ray R.

∠QRS + ∠SRN = 180°

140° + ∠SRN = 180°

∠SRN = 40°

Where ∠SRN and ∠OMQ are opposite angle

So, ∠SRN  = ∠OMQ = 40°

Now 

∠OPQ + ∠MPQ = 180°

100° + ∠MPQ = 180°

∠MPQ = 180° - 100° = 80°

In triangle PQM, 

∠OPQ+ ∠MPQ + ∠OQM = 180°

40°+80° + ∠OQM = 180°

120° + ∠OQM = 180°

∠OQM = 180° - 120° = 60°

therefore, ∠PQR = ∠OQM = 60°