In the given figure, AB is parallel to EF. ED is parallel to CB and angle APE is 60 degrees.
What is the value (in degrees) of angle EQC?

Correct option is A

Given:

AB ∥ EF

ED ∥ CB

∠APE = 60°

Find ∠EQC

Concept Used:

Corresponding angles between parallel lines

Vertically opposite angles

Formula Used:
Angles formed by parallel lines are equal.

Solution:

At point P, ∠APE = 60°.

Since AB ∥ EF and ED ∥ CB, the angle formed between EF and CB at Q will be equal to the angle formed between AB and ED at P.

Thus, the acute angle at Q is also 60°.

∠EQC is vertically opposite to this acute angle, so:

∠EQC = 60°

Therefore,

∠EQC = 60°