In a triangle ABC, ∠B = 90°, ∠C = 45° and D is the midpoint of AC. If AC = $$4\sqrt2$$​ units, then BD is:

Correct option is A

Given:

In triangle ABC, ∠B =$$90^\circ, ∠C= 45^\circ.$$​​

D is the midpoint of AC.

AC = $$4\sqrt{2}$$​ units.

Concept Used:

For a right-angled triangle, the length of the median to the hypotenuse is given by:

BD =$$\frac{AC}{2}$$​

Solution:

Given AC =$$4\sqrt{2}$$​, the length of the median BD is:

BD $$= \frac{4\sqrt{2}}{2} = 2\sqrt{2}$$​